This article is quite helpful and answers many of my questions. But i have one more problem in hand regarding this seondary id which i am not able to solve. Please put forward some solution to this,

I am creating a RCP application. I need to open multiple instances of the same view but with different data. I did it by setting secondary id for different instances of the same view. Specifically, my problem is as follows: Please take a look,

i have a graph view called “Views.GraphView”. I opened different instances of it from a command called “openGraphView” to show different graphs. the command is as follows:

page.showView(“Views.GraphView”, Integer.toString(instanceNum++), IWorkbenchPage.VIEW_ACTIVATE);

Now, I have a command called “TreeLayout” on this “Views.GraphView” toolbar, which suppose to change the layout of the graph and it will operate on each instace of the view. But for this, i think, i need to identify which instance of the view is active. the “TreeLayout” command looks something like this:

IViewPart findView = HandlerUtil.getActiveWorkbenchWindow(event).getActivePage(). findView( “Views.GraphView”); //i think in the findView i need to give the id of the view [but how can i put the secondary id!!]

GraphView view = (GraphView) findView; view.changeLayout(); //i wrote this method in the graph view to change the layout

//i just tried to print the secondary id, but it did not print anyting System.out.println(“From treelayout command:- ” + view.getViewSite().getSecondaryId());

So how can i identify whcih instance of the view is currently active and to operate on it? Please, provide some solution.

Thanks,

-Syeed

Nice post. I blogged (http://manuelselva.wordpress.com/2008/05/15/multi-instances-of-a-viewpart/) a while ago about the same subject.

My solution was to use the “Primary view == the one with no secondary ID” to access all the “secondary” views. Nevertheless I will keep in mind your solution for my next multi instances views ..

Manu